Math, asked by nirmalsamdani, 7 months ago

The annual rate of growth of population of a certain city is 8%. If its present population is 196830, what was the population year ago.

Answers

Answered by annamaryjoseph977
2

Answer:

The annual rate of growth in population of a certain city is 8 percent

So the annual rate of growth population of a certain city is 8% and its present population is 196830. imagine 3 years ago the population was x.

Step-by-step explanation:

Answered by TheHeart
3

Answer:

The correct question should be =The annual rate of growth of population of a certain city is 8%. If its present population is 196830, what it was the population 3 years ago?

Given details are:

Annual growth rate of population of city is =8%

Present population of city is =196830

What to find = population of city 3 years ago?

Solution :

Let population of city 3 years ago be= X

By using the formula

A=P[1+R/100]

196830=x[1+8/100] [1+8/100] [1+8/100]

196830=x[25/27] [25/27] [25/27]

196830=x[1.08] [1.08] [1.08]

196830=1.259712x

X= 196830/1.259712

X=156250 Answer

So population 3 years ago was 156250.

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