Question

the annual rate of growth of population of a town is 12% if its present population is 186040 what it was 2 years ago

Answer 1

$let \: it \: was \: x \\ therefore \: x( { \frac{112}{100}) }^{2} = 186040 \\ x( { \frac{28}{25}) }^{2} = 186040 \\ \\ x( \frac{784}{625} ) = 186040 \\ x = \frac{186040 \times 625}{784} \\ x = 148310 approx$

Answer 2

It was 148309 2 years ago

Step-by-step explanation:

Let the population 2 years ago be x

We are given that the annual rate of growth of population of a town is 12%

So, Population after 1 year =$x+12\%x=x+\frac{12}{100}x=x+0.12x=1.12x$

Population after 2 years=$1.12x+12\%(1.12x)=1.12x+0.12(1.12x)=1.2544 x$

We are given that its present population is 186040

So, $1.2544x=186040$

$x=\frac{186040}{1.2544}$

x=148309.94

Hence It was 148309 2 years ago

#Learn more:

The annual rate of growth in population of a town is 10%.If its present population  is 26620,the population 3 years ago was?​

https://brainly.in/question/13021109