Math, asked by pawarkirti04, 7 months ago

The annual salaries of employees in a large company are approximately normally distributed, with a mean of $50,000 and a standard deviation of $20,000. (a) What is the probability that an employee earns a salary greater than $100,000? The company provides free public transport to the employees that earn the lowest 10% of salaries. Less than what salary does a person have to earn to qualify for free public transport? (c) A sample of 16 employees is now taken. What is the probability that the sample mean is greater than $40,000?

Answers

Answered by dipakghi1
0

Answer:

ANSWER

Let x be the annual salary of employees in a large company.

x has μ=50000,σ=20000.

We know that for given x,z=

σ

x−μ

We have to find the percent of people earning between 45,000 and 65,000

First let us find P(45000<x<65000)

For x=45000,z=

20000

45000−50000

=−0.25

and for x=65000,z=

20000

65000−50000

=0.75

∴P(45000<x<65000)=P(−0.25<z<0.75)

=P(z<0.75)−P(z<−0.25)

=0.7734−(1−0.5986) (from normal distribution table)

=0.372

∴P(45000<x<65000)=0.372=37.2%

Hence the percent of people earning between 45,000 and 65,000 is 37.2%

Answered by aashishverma3333
0

Step-by-step explanation:

The annual salaries of employees in a large company are approximately normally distributed with a mean of $50,000 and a standard deviation of $20,000. a) What is the ... earns a salary greater than $100,000 b) The company provides free public transport to the employees that earn the lowest 10% of salaries.

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