Question

The anodic half cell of lead acid battery is recharged using electrcity of 0.05 farady. The amount of pbso4 electrolyzed in g during the process is

Answer 1

Answer:

The amount of PbSO₄ electrolyzed by 0.05 Farad of electricity will be 7.57 grams

Explanation:

The reaction involved in the process is given below:

PbSO₄ -----------> Pb²⁺ + SO₄²⁻

Pb²⁺ + 2H₂O -------> PbO₂ + 4H⁺ + 2e⁻

Clearly 1 mole of PbSO₄ produces 2 moles of electrons(2 faraday)

Since the molar mass of PbSO₄ is 303 g

=> 303 grams of PbSO₄ produces 2 faraday of electricity

=> 0.05 Faraday will gives = (303/2) x 0.05

= 7.57 grams of PbSO₄

Hence the amount of PbSO₄ electrolyzed by 0.05 Farad of electricity will be 7.57 grams