the answer is b. can anyone explain why?
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elocity is a vector, it can change in two ways: its magnitude can change and its direction can change. Either change gives rise to an acceleration. For circular motion at constant speed, the velocity is always tangential to the circular path, and therefore its direction is continuously changing even though its magnitude is constant. Therefore, the object has an acceleration. It can be shown that the magnitude of the acceleration ac for uniform circular motion with speed v in a path of radius Ris
ac = v2R,
and that the direction of the acceleration is inward toward the center of the circular path. This is illustrated in Figure 1.
n the object equal in magnitude to mac and in the direction of ac.Circular motion with speed v in a path of radius R has period (time for one revolution) T and frequency (revolutions/s)
f = 1/T.
Since the object travels a distance 2πR (the circumference of its circular path) in time T the speed v is equal to
v = 2πRT = 2πRf
and
ac = 4π2f 2R.
The setup for the experiment is shown in Figure 2. When the plastic tube is moved in a small circle above your head, the racketball moves around in a horizontal circle at the end of a string that passes through the tube and has a mass hanger with slotted masses suspended from its lower end.Applying
ΣF = ma
to the stationary mass hanger gives
Fstring = Mg,
where Fstring is the tension in the string and M is the sum of the masses of the mass hanger and the slotted masses that are placed on it.
ac = v2R,
and that the direction of the acceleration is inward toward the center of the circular path. This is illustrated in Figure 1.
n the object equal in magnitude to mac and in the direction of ac.Circular motion with speed v in a path of radius R has period (time for one revolution) T and frequency (revolutions/s)
f = 1/T.
Since the object travels a distance 2πR (the circumference of its circular path) in time T the speed v is equal to
v = 2πRT = 2πRf
and
ac = 4π2f 2R.
The setup for the experiment is shown in Figure 2. When the plastic tube is moved in a small circle above your head, the racketball moves around in a horizontal circle at the end of a string that passes through the tube and has a mass hanger with slotted masses suspended from its lower end.Applying
ΣF = ma
to the stationary mass hanger gives
Fstring = Mg,
where Fstring is the tension in the string and M is the sum of the masses of the mass hanger and the slotted masses that are placed on it.
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