The answer is
The cost of fencing Rahul's field is = 1,80,000
The cost of fencing Ramu's field is = 1,80,000
ramu can plant more trees ;1000 trees more
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3
Rahul own a rectangular field of length = 400 m
breadth = 200 m
perimeter of a rectangle = 2( l + b )
= 2(400+200)
= 2(600)
= 1200
His friend ramu owns a square field of length = 300 m
perimeter of a square = 4 × side
= 4 × 300
= 1200
The cost of fencing the two fields at rate = 150 per meter
Rahul field = 1200 × 150
= 1,80,000
Ramu field = 1200 × 150
= 1,80,000
1,80,000/1000 = 180
1,80,000/180 =1000
breadth = 200 m
perimeter of a rectangle = 2( l + b )
= 2(400+200)
= 2(600)
= 1200
His friend ramu owns a square field of length = 300 m
perimeter of a square = 4 × side
= 4 × 300
= 1200
The cost of fencing the two fields at rate = 150 per meter
Rahul field = 1200 × 150
= 1,80,000
Ramu field = 1200 × 150
= 1,80,000
1,80,000/1000 = 180
1,80,000/180 =1000
Answered by
2
Given the length of the rectangular field of Rahul = 400.
Given the breadth of the rectangular field of Rahul = 200.
We know that Area of the rectangular field = Length * Breadth
= 400 * 200
= 80000 sq.m. --------------- (1)
We know that perimeter of rectangular field = 2(l + b)
= 2(400 + 200)
= 1200m.
Given that his friend Ramu owns a Square field of length 300m.
We know that Area of the square field = side * side
= 300 * 300
= 90000 sq.m -------------- (2)
We know that Perimeter of square field = 4 * Side
= 4 * 300
= 1200m.
Given that cost of fencing per m^2 = 150.
Therefore, Total cost of fencing both the fields = 1200 * 150
= 180000.
Given that in every 10 square meter area, one tree can be planted.
From the equation (1)
The total number of trees can be planted by Rahul = 80000/10
= 8000.
From the equation (2),
The total number of trees can be planted by Ramu = 90000/10
= 9000.
Therefore Ramu can plant 1000 trees more than Rahul.
Hope this helps! ----------------------- Good Luck..
Given the breadth of the rectangular field of Rahul = 200.
We know that Area of the rectangular field = Length * Breadth
= 400 * 200
= 80000 sq.m. --------------- (1)
We know that perimeter of rectangular field = 2(l + b)
= 2(400 + 200)
= 1200m.
Given that his friend Ramu owns a Square field of length 300m.
We know that Area of the square field = side * side
= 300 * 300
= 90000 sq.m -------------- (2)
We know that Perimeter of square field = 4 * Side
= 4 * 300
= 1200m.
Given that cost of fencing per m^2 = 150.
Therefore, Total cost of fencing both the fields = 1200 * 150
= 180000.
Given that in every 10 square meter area, one tree can be planted.
From the equation (1)
The total number of trees can be planted by Rahul = 80000/10
= 8000.
From the equation (2),
The total number of trees can be planted by Ramu = 90000/10
= 9000.
Therefore Ramu can plant 1000 trees more than Rahul.
Hope this helps! ----------------------- Good Luck..
siddhartharao77:
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