The answer is wrong. Can anyone give full method explanation??? He/she will be brainliest!
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6Ω and 12Ω are parelllel. Their equivalent is (6 × 12) / (6 + 12) = 4Ω
4Ω is in series with 8Ω. Their equivalent is 4 + 8 = 12Ω
12Ω and 12Ω are in parellel. Their equivalent = 12 × 12 / (12 + 12) = 6 Ω
Now, 6 Ω and 18 Ω are in series. Their equivalent is 6 + 18 = 24 Ω
So, equivalent resistance of circuit is 24 Ω
Total current in the circuit = V / R
= 24 volts / 24 Ω
= 1 A
By Kirchhoff’s law current passing through 18 Ω resistor will also be equal to 1 A
4Ω is in series with 8Ω. Their equivalent is 4 + 8 = 12Ω
12Ω and 12Ω are in parellel. Their equivalent = 12 × 12 / (12 + 12) = 6 Ω
Now, 6 Ω and 18 Ω are in series. Their equivalent is 6 + 18 = 24 Ω
So, equivalent resistance of circuit is 24 Ω
Total current in the circuit = V / R
= 24 volts / 24 Ω
= 1 A
By Kirchhoff’s law current passing through 18 Ω resistor will also be equal to 1 A
BlankNGNL:
Hey How is the current 1.33 A??
It's Supposed to be 1A.
@BlankNGNL How it’s supposed to be 1 A? You should prove it.
@Mann You’re welcome. In future don’t report any answer until you’re sure about it.
Oh sorry bro
No problem.
Current through the 18 ohm resistor should be V/Req=24/(18+6).
How did you write voltage across 18 ohm As 24. If it's true the voltage through 6ohm must be zero which ia not possible.
@BlankNGNL Yes... I was thinking this only... You are correct
Answer edited. Thanks @BlankNGNL :)
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