Question

the answer of this question is 4000°Ato 8000°A​

Answer 1

its wavelength range will be

$\frac{3 \times 10 {}^{8} }{3.75 \times 10 {}^{14} } \: \: to \: \: \frac{3 \times 10 {}^{8} }{7.5 \times 10 {}^{14} } \\ = 8 \times 1 {}^{ - 7} m \: \: to \: \:4 \times 10 {}^{ - 7} m$

4000å to 8000å