The AP formed by sequence i.e. number of plants by students is _
Answers
Step-by-step explanation:
We have,
Total strength of students in the auditorium =1000
Number of students left in the auditorium when first batch of 25 students leave the auditorium =1000−25=975
Number of students left in the auditorium when second batch of 25 students leave the auditorium =975−25=950
Number of students left in the auditorium when third batch of 25 students leave the auditorium =950−25=925 and so on.
Thus, the number of students left in the auditorium at different stages are
1000,975,950,925,....
Clearly, it is an A.P. with first term 1000 and a common difference −25.
(ii) We know that if P is the principal and r% per annum is the rate of interest, compound annually,
then the amount A
n
at the end of n years is given by
A
n
=P(1+
100
r
)
n
Here P=Rs100 and r=4.
∴A
n
=100(1+
100
4
)
n
=100×(
25
26
)
n
=100×(1.04)
n
Thus, the amount of monkey in the account at the end of different years is given by
Rs100×1.04,Rs100×(1.04)
2
,Rs100×(1.04)
3
,....
or Rs104,Rs108.16,Rs112.48,... Clearly, it is not forming an A.P. as common difference is not same.