Question

The ap is an 2 ,11 ,20,29 which term of the ap is 560

Answer 1

a=2
d=9
n term of AP is 560
n term of AP= a+(n-1)d
560= 2+(n-1)9
560-2=(n-1)9
558=(n-1)9
558/9=n-1
62=n-1
63=n

Answer 2

Given:

An A.P. 2, 11, 20, 29.

To find:

Which term of the given A.P. is 560.

Solution:

The term of the A.P. which is 560 is 63rd.

To answer this question, we need to follow the following steps:

As we know the nth term of an AP that has a = first term, d = common difference and n = number of terms till the nth term is given by using the formula:

${n}^{th} \: term = a + (n - 1)d$

Now,

according to the question,

We have an A.P. 2, 11, 20, 29

where the first term or a = 2

Common difference or d

$= 11 - 2$

$= 9$

nth term = 560

So,

Using the above-mentioned formula:

$560 = 2 + (n - 1)9$

$560 = 2 + 9n - 9$

$560 = - 7 + 9n$

$567 = 9n$

$n = 63$

Hence, the 63rd term of the A. P. is 560.