Question

the ap whose third term is 16 and the difference of 5 th term from the 7 term is 12 then the ap is​

Answer 1

Answer:

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Answer 2

Answer:

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Step-by-step explanation:

a3=16

a+2d=16

a=16-2d. -©

a7-a5=12

a+6d-a-4d=12

2d=12

d=6

put d=6 in eq.©

a=16-2(6)

a=16-12

a=4

then the required ap is

4,10,16,22,28,34,40,46,52,58,64,70,...........infinity