The apparent depth of an object at the bottom of a tank filled with a liquid of refractive index 1.3 is 7.7 cm. What is the actual depth of the liquid in the tank?
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double check the answer I havent revised this chapter in forever
but I think
n1 / n2 = d2 / d1
1.33 / 1 = d2 / 7.7
d2 or actual depth = 7.7 x1.3 = 10
n1 refractive index liquid , d1 depth in this liquid
2 is the same quantities in air
again double check I dont remember optics completely
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