Question

The apparent depth of an object at the bottom of tank filled with a liquid of refractive index 1.3 is 7.7cm. What is the actual depth of the liquid in the tank?

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Answer 1

Answer:

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Answer 2

Answer:

d = 10.01 cm

Explanation:

Given, Apparent depth of a object($d'$) = 7.7 cm

Refractive index of the liquid(μ) = 1.3

To calculate the actual depth of the object present in the liquid we use:

real depth(d) = apparent depth($d'$) × refractive index(μ)

d = 7.7 cm × 1.3

⇒ d = 10.01 cm

Therefore, the actual depth of the object in the liquid is 10.01.

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