Physics, asked by bunnybabli8912, 1 year ago

the apparent power drawn by an a.c. circuit is 10 kva and active power is 8 kw. the reactive power in the circuit is

Answers

Answered by ananya4412
12

The apparent power drawn by an A.C. circuit is 10 kVA and active power is 8 kW. The reactive power in the circuit is

A. 4 kVAR

B. 6 kVAR

C. 8 kVAR

D. 16 kVAR

Answer: Option B

Answered by Anonymous
1

Given:

The apparent power drawn by an a.c. circuit = 10 kw

The active power = 8 kw

To find:

Find the reactive power of the circuit.

Solution:

It is given that the apparent power drawn by the circuit = 10 kw

The active power = 8 kw

So we know that

(apparent power)² =  (active power)² + (reactive power)²

We will use this formula to find the reactive power

10² = 8² + (reactive power)²

100 - 64 = (reactive power)²

36 = (reactive power)²

reactive power = 6 kw

Therefore the reactive power in the circuit is 6 kw.

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