The apparent weight of a person in a lift which is moving down with uniform acceleration is _______.
A) greater than the weight when the person is stationary B) twice the weight when the person is stationary C) less than the weight when the person is stationary D) same as the weight when the person is stationary
Answers
Answered by
0
Answer:
Option C
Explanation:
When the man in lift is accelerated downward, apparent weight
W = m(g-a)
When lift is accelerated upward
W = m(g+a)
Hope it helps
Answered by
0
Answer:
Don't know ur answer gentleman SORRY
Similar questions