the apparent weight of mass in a lift moving up is 80kg when its weight in the stationary lift is 60kg . if the same lift now moves up with same retardation, the weight of the mass will be
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Heya user !!!
Here's the answer you are looking for
⏩When a lift moves up with an acceleration a, then weight of any object inside it becomes m(g+a)
So, here
⏩m(g+a) = 80
and
⏩mg = 60
So, m = 6 as g = 10
so, m(g+a)=80
6(10+a) = 80
10 + a = 40/3
⏩a = 10/3 m/s²
⏩Now the acceleration becomes retardation, so a = –10/3m/s²
W = 6 {10 + (-10/3)}
W = 6(10-10/3)
W = 6(20/3) = 40N
Since weight is 40N, mass becomes 40/10 = 4kg
★★ HOPE THAT HELPS ☺️ ★★
Here's the answer you are looking for
⏩When a lift moves up with an acceleration a, then weight of any object inside it becomes m(g+a)
So, here
⏩m(g+a) = 80
and
⏩mg = 60
So, m = 6 as g = 10
so, m(g+a)=80
6(10+a) = 80
10 + a = 40/3
⏩a = 10/3 m/s²
⏩Now the acceleration becomes retardation, so a = –10/3m/s²
W = 6 {10 + (-10/3)}
W = 6(10-10/3)
W = 6(20/3) = 40N
Since weight is 40N, mass becomes 40/10 = 4kg
★★ HOPE THAT HELPS ☺️ ★★
Answered by
1
Answer:
it is the solution of above question
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