Question

the applied potential difference across a given resistor is altered so that the heat produced per second increases by factor of 16 . by what factor the applied potential difference changes.

Answer 1

Ans. Let original Potential difference applied is V and original Heat Produced is H.

Then, H = V2tRV2tR…………(1)

New potential difference is V' and Heat Produced after change is H'.

Then,

H′=V′2tRH′=V′2tR …………(2)

According To question,

H' = 16H

=>V′2tR=16×V2tR=>V′2tR=9×V2tR

=> V'2 = 16V2

=> V' = 4V

So potential difference is increased by a factor 4.

Answer 2

here 's ur answer !!