The approximate change in the volume of a cube of side x metres caused by increasing the side by 3% is A. 0.06 x^ 3 m ^3 B. 0.6 x^ 3 m^ 3 C. 0.09 x^ 3 m ^3 D. 0.9 x ^3 m ^3
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HELLO DEAR,
side of cube = x meter.
increase in side by 3%.
VOLUME OF cube = x³m³.
dV/dx = 3x²
GIVEN increment in side = 3% = 3x/100 = 0.03x
now, the approximate change in volume V of cube = ∆V - dV = dV/dx * ∆x
dV/dx * ∆x = 3x² * (0.03x)
= 0.09x³m³
hence, the approximate change in volume is ; 0.09x³m³
hence, option (C) is correct,
I HOPE ITS HELP YOU DEAR,
THANKS
side of cube = x meter.
increase in side by 3%.
VOLUME OF cube = x³m³.
dV/dx = 3x²
GIVEN increment in side = 3% = 3x/100 = 0.03x
now, the approximate change in volume V of cube = ∆V - dV = dV/dx * ∆x
dV/dx * ∆x = 3x² * (0.03x)
= 0.09x³m³
hence, the approximate change in volume is ; 0.09x³m³
hence, option (C) is correct,
I HOPE ITS HELP YOU DEAR,
THANKS
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