The approximate number of molecules present in 3g of H2O is
A) 3×10^23
C) 1 x 10^23
B)3×6.01 x 10^23
D) 2 x10^23
Answers
Answered by
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THE 18 g of water have =6.022×10^23
1g = 6.022×10^23/18
3g=6.022×10^23/18×3
=》3.455×10^23
(A) ANSWER
rameensattar:
<6.02×10^23 ÷18) ×3
u have wrote this
what i need to know
this question is not my
this ans will be only when we divide 6.02×10 ^23 by 18
ok
yes
hun
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