Question

the approximate size of the nucleus of 28 64Ni is :

a) 3 fm b) 4 fm c) 5 fm d) 2 fm

Answer 1

Nuclear size is given by the expression:

r = R0A⅓
where r is the radius of the nucleus
R0 is a constant whose value is equal to 1.25 fm         (fm is fermi units)
A is atomic mass of element

Thus for 64Ni, we have 
r  = 1.25 ×(64)⅓
r  = 1.25 ×4
r = 5 fm

Thus nuclear size  of Ni is 5 fm.