Question

The approximate time t(in second) that it takes an object to fall d meters is given bye the formula
$t = \frac{ \sqrt{d} }{4}$
if a man at the top of the building drops a coin ,and it takes the coin 8 second to hit the ground,how tall is the building?


plss help ma


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Answer 1

GivEn:

• The approximate time t(in second) that it takes an object to fall d meters is given bye the formula $t = \frac{ \sqrt{d} }{4}$
• From top of a building, a coin is dropped and it takes 8 second to hit ground.

To finD:

• How tall the building is ?

Solution:-

Here, given equation is :

• $\large{\tt{\green{t \: =\: \frac{ \sqrt{d} }{4}}}}$

Where,

• t = 8 second ••••••••(given)
• d = x meter ••••••••( suppose)

Put given values in given formula:-

$\large{\sf{t~=~\frac{\sqrt{d}}{4}}}$

⟹$\large{\sf{8~=~\frac{\sqrt{x}}{4}}}$

⟹$\large{\sf{\sqrt{x}~=~ 8×4}}$

⟹$\large{\sf{\sqrt{x}~=~ 32}}$

⟹$\large{\sf{x~=~ \sqrt{32}}}$

⟹ $\large{\boxed{\bf{x ~=~ 5.657}}}$

Therefore,

The building is 5.657m tall.