Question

The approximate value of g at an altitude above earth equal to one earth diameter is

Answer 1

Hey buddy,

# Answer- g' = g/9 = 1.09 m/s^2

# Explaination-
Gravitational acceleration due to earth at distance r from earth's centre is given by
g = GM/r^2

At height equal to earths diameter
h = 2R
r = R+h = R+2R = 3R

Gravitational acceleration at h=2R
g' = GM/9R^2
g' = g/9
g' = 9.8/9
g' = 1.09 m/s^2

Gravitational acceleration at height equal to earths diameter is 1.09 m/s^2.

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