The approximate value of x where x is equal to sin 2 degree cos 2 degree
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Given : x = sin2°Cos2°
To find : The approximate value of x
Solution:
x = sin2°Cos2°
=> x = 2sin2°Cos2°/2
=> x = Sin4°/2
180° = π
=> 1° = π/180
=> 4° = 4π/180
=> 4° = 2π/90
=> x = Sin( 2π/90) / 2
Multiplying & dividing by π/90
=> x = ( π/90) Sin( 2π/90) / (2(π/90) )
=> x = ( π/90) Sin( 2π/90) / (2π/90 )
2π/90 tends to 0
=> Sin Sin( 2π/90) / (2π/90 ) = 1
=> x = π/90
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