Physics, asked by aishapatel2612, 10 months ago

The approximate value of x where x = (sin 2°) (cos 2°), is :
(A) /90 (B) 2 (C) 1 (D) /45

Answers

Answered by pdipesh1612
0

Answer:

(c)1

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Answered by kiyara01
3

Explanation:

To Find :

The value of X

Solution :

We know the trigonometric relation

           Sin2θ = 2SinθCosθ

           SinθCosθ = Sin2θ/2

By substituting the value θ=2° in the above relation

           Sin2°Cos2° = Sin2(2)/2

                               = Sin4° / 2

                               =0.06976\2

           Sin2°Cos2° =0.03488

The value of  X =Sin2°Cos2° is 0.03488

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