Question

the approximately temperature at which one mol L-1 of a sample of pure ideal gas exhibits a pressure of 101.325 KPa is____plz help ❤

Answer 1

Hey.

Here is your answer.

For every Ideal Gas,

We know that, PV = nRT

where, P = Pressure

V = Volume

n = no. of moles

R = Universal Gas Constant

T = Absolute Temperature

So, following this we are given

Pressure = 101.325 kPa

Molarity of the gas, M = 1 mol/ L

which is M = n / V

And we know that ,

1 atm = 101.325 kPa

So, Putting the values as in

the attachment answer we can get as

T = 12.18621 K.

Please see attachment for detailed solution .

Thanks