Question

The aquarium with the length 45 cm, the width 25 cm and the height 25 cm contains 19 liters of water. What is the height of an empty part of the aquarium?

Answer 1

$\huge\mathfrak\pink{Given:-}$

• The length of the aquarium is 45 Cm.
• The width of the aquarium is 25 Cm.
• The height of the aquarium is 25 C.
• Contain 19 litres of water.

$\huge\green{To \: find :-}$

• Height of an empty part of the aquarium.

$\huge\mathfrak\red{Let \: us \: assume : }$

• Empty height of the aquarium be x
• 19litre=19000cm³ because 1 litre = 1000cm³

$\huge\mathfrak\blue{solution:-}$

Volume of aquarium = length×width×height

volume of aquarium = 45cm×25cm×25cm

volume of aquarium = 28125cm³

[volume of empty part of aquarium + volume of water in the aquarium=total volume of aquarium]

(45cm×25cm× Xcm+19000cm³=28125cm³

1125x cm³=28125cm³-19000cm³

1125x cm³=9125cm³

$x = \frac{9125 {cm}^{3} }{1125 {cm}^{3} }$

$x = 8.1$

Empty height of the aquarium is8.1

[Thanks]

Answer 2

Answer:

ALWAYS BE A BRAINLY.

THANKS.