Math, asked by Anonymous, 15 days ago

The arc length of a circle having radius 15 cm and subtending an angle 105 degree at the centre of circles is .





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Answered by llTheUnkownStarll
8

Question:

  • The arc length of a circle having radius 15cm and subtending an angle 105° at the centre of circle is?

Answer:

  • Length of arc is 27.5 cm (approx).

Step-by-step Explanation:

Given:

  • Radius of circle (r) = 15 cm
  • Angle at the centre of circle (θ)105°

To Find:

  • Length of arc of a circle?

Required Formula:

 {\color{orange}\bigstar}\:{\underline{\boxed{\frak{Length\:of\:arc = \dfrac{\theta}{360}\:\times\:2\pi r}}}}

Where,

  • θ denotes angle at centre
  • pi denotes angle at centre π 
  • r denotes radius of circle

We have,

  • Angle at centre (θ)105°
  • Pi (π)22/7
  • Radius of circle (r)15 cm

Solution:

\begin{gathered} \begin{gathered}   \underline{ \underline{\pmb {\frak{ \color{red}{According  \: to \:  the \:  question}}}}}\\ \\  \hookrightarrow\:\sf Length\:of\:arc = \dfrac{\theta}{360}\:\times\:2\pi r\end{gathered} \\  \\ \underline{ \frak \color{navy}{Putting \:  all \:  values \:  in  \: the \:  formula \:  we  \: get,}} \\  \\ \begin{gathered}\\ \hookrightarrow\:\sf Length\:of\:arc = \dfrac{\cancel{105}}{360}\:\times\:2\:\times\:\dfrac{22}{\cancel{7}}\:\times\:15\end{gathered} \\  \\ \begin{gathered}\\ \hookrightarrow\:\sf Length\:of\:arc = {\cancel{\dfrac{15}{360}}}\:\times\:2\:\times\:22\:\times\:15\end{gathered} \\  \\ \begin{gathered}\\ \hookrightarrow\:\sf Length\:of\:arc = \dfrac{1}{\cancel{24}}\:\times\:\cancel{44}\:\times\:15\end{gathered} \\  \\ \begin{gathered}\\ \hookrightarrow\:\sf Length\:of\:arc = \dfrac{1}{6}\:\times\:11\:\times\:15\end{gathered} \\  \\ \begin{gathered}\\ \hookrightarrow\:\sf Length\:of\:arc = \dfrac{11\:\times\:15}{6}\end{gathered} \\  \\ \begin{gathered}\\ \hookrightarrow\:\sf Length\:of\:arc = \dfrac{165}{6}\end{gathered} \\  \\ \begin{gathered}\\ \hookrightarrow\:\underline{\boxed{\frak{Length\:of\:arc\:\approx\:27.5\:cm \:  approx. \: }}} \orange\bigstar\end{gathered}\end{gathered} \\  \\  \\    \underline{\sf{Hence, length \:  of  \: the \: arc  \: is  \textsf{\textbf{27.5 cm (approx)}}}.}

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