Math, asked by ujwalshankar746, 6 months ago

the are bounded by the curves y=cosx and y=sinx between the ordinates x=0 and x=3pie/2

Answers

Answered by kmahima922
0

Answer:

ANSWER

The desired are =∫

0

π/4

(cosx)dx

+∫

π/4

5π/4

(sinx−cosx)dx+∫

5π/4

3π/2

(cosx−sinx)dx

=2[sinx+cosx]

0

π/4

+[−cosx−sinx]

π/4

5π/4

(As the first and third integrals are equal in magnitude )

=2(

2

1

+

2

1

−1)+(

2

1

+

2

1

+

2

1

+

2

1

)

2

8

−2=4

2

−2

solution

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