the are bounded by the curves y=cosx and y=sinx between the ordinates x=0 and x=3pie/2
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The desired are =∫
0
π/4
(cosx)dx
+∫
π/4
5π/4
(sinx−cosx)dx+∫
5π/4
3π/2
(cosx−sinx)dx
=2[sinx+cosx]
0
π/4
+[−cosx−sinx]
π/4
5π/4
(As the first and third integrals are equal in magnitude )
=2(
2
1
+
2
1
−1)+(
2
1
+
2
1
+
2
1
+
2
1
)
2
8
−2=4
2
−2
solution
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