Question

The are of a square field is 5184m sq . Find the area of a rectangular field, whose perimeter is equal to the perimeter of the square field and whose length is twice of its breadth.​

Answer 1

Given:-

• the area of square is=5184m²

$\huge\underline\mathrm{Solution:-}$

s×s = 5184

s² = 5184

s = √5184

s=72

• according to problem,

l = 2x

b = x

we know that,

perimeter of square=perimeter of rectangle

→4s = 2(l+b)

→ 4×72 = 2(2x+x)

→288 = 6x

→x = 288/6

→x = 48

• from problem,

l=2x

l =2×48

l =96

b = x

b = 48

therefore, length is 96

               breadth is 48

area of rectangle = l × b

                            = 96 × 48

                             =4608 m²

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Answer 2

Given :-

• Area of square = 6889 m^2

we have to find perimeter of square =?

Now

• Area of square = side^2

=>5184 m^2 = side^2

=>72m =side of square

Now

• perimeter of square => 4× side .

=> 4×72=288m

Now,

Let,

The breadth of rectangle be x

Then the length be 2x

As we know that,

 perimeter of a rectangle =2(length+breadth)

And, perimeter of square = perimeter of rectangle = 288m 

288 = 2(x + 2x)

288/2 = 3x

144 = 3x

144/3 =x

48 = x

Then,

• breadth of rectangle = x = 48 m 

• and length of rectangle = 2x = (2×48) = 96m 

Now,

• Area of rectangle = length×breadth

Here,

• Area of rectangle =  48×96 

• Area of rectangle =4608 m^2