Question

the are of a trapezium is 120 sq cm and the perpendicular distance between its parallel side is 8 cm. find the lengths of the parallel sides, if their difference is 6 cm.

Answer 1

here is solution of ur problem......

Answer 2

The lengths of the parallel sides are 13 cm and 7 cm

Step-by-step explanation:

Let the parallel side be x and y

Area of trap. = $\frac{1}{2}(\text{Sum of parallel sides}) \times Height$

The perpendicular distance between its parallel side is 8 cm

So, Height = 8 cm

Area of trap. = $\frac{1}{2}(x+y) \times 8$

The area of a trap. is 120 sq cm

So, $\frac{1}{2}(x+y) \times 8=120$

$(x+y)=\frac{120 \times 2}{8}$

$(x+y)=30$---1

We are given that their difference is 6 cm.

So, x-y = 6 ---2

Add 1 and 2

2x=36

x=13 cm

x-y=6

13-y=6

13-6=y

7=y

Hence the lengths of the parallel sides are 13 cm and 7 cm

#learn more:

The difference between the lengths of the parallel sides of a trap

is 8 cm, the perpendicular distance between these sides is 24 cm and the

area of the trap is 312 cm. Find the length of each of the parallel side ​

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