The are of a trapezium is 210cm and its height is 14cm. If one of the parallel side is longer than the other by 12cm,find the two parellel sides.
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Let one parallel side be X
thus
the other side will be 2x
area of a trapezium=
1/2×height×(sum of parallel sides)
210 cm² = 1/2×14×(2x+X)
210 = 1/2 × 14 × (3x)
210 = 7×(3x)
210 = 21x
which implies
X=210/21=10
thus one side is 10 cm and. the other side is 20 cm
thus
the other side will be 2x
area of a trapezium=
1/2×height×(sum of parallel sides)
210 cm² = 1/2×14×(2x+X)
210 = 1/2 × 14 × (3x)
210 = 7×(3x)
210 = 21x
which implies
X=210/21=10
thus one side is 10 cm and. the other side is 20 cm
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