Question

The are of square field is 60025 m^2. A man cycles along its boundary at 18km/hr. In how much time will he return at the same point.

( please keep in mind this question is based on the chapter "Square and Square Roots")

Answer 1

Answer:

I hope u got u r answer

Answer 2

$\displaystyle\large\underline{\sf\red{Given}}$

✭ Area of a square field is 60025 m²

✭ A man cycle around its boundary will a speed of 18 km/h

$\displaystyle\large\underline{\sf\blue{To \ Find}}$

◈ How much time would he spend to complete one round?

$\displaystyle\large\underline{\sf\gray{Solution}}$

So here we may first find the perimeter of the square and then use he formula for speed, interchange the Values and get our Time!!

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$\underline{\bigstar\:\textsf{According to the given Question :}}$

Area of a square is given by,

$\displaystyle\underline{\boxed{\sf Area_{square} = Side^2}}$

• Area = 60025 m²

Substituting the values,

➝ $\displaystyle\sf Area = Side^2$

➝ $\displaystyle\sf 60025 = Side^2$

➝ $\displaystyle\sf \sqrt{60025} = Side$

➝ $\displaystyle\sf \purple{Side = 245 m}$

Then the perimeter of the field will be,

➢ $\displaystyle\sf Perimeter_{Square} = 4\times Side$

➢ $\displaystyle\sf Perimeter = 4\times 245$

➢ $\displaystyle\sf \green{Perimeter = 980 \ m}$

Now we shall convet the speed to m/s

»» $\displaystyle\sf 18 \ km/s = 18\times \dfrac{5}{18}$

»» $\displaystyle\sf \orange{Speed = 5 \ m/s}$

Now the speed of a body is given by,

➳ $\displaystyle\sf Speed = \dfrac{Distance}{Time}$

So here,

➳ $\displaystyle\sf Time = \dfrac{Perimeter}{Speed}$

Substituting the values,

›› $\displaystyle\sf Time = \dfrac{980}{5}$

›› $\displaystyle\sf \pink{Time = 196 \ sec}$

$\displaystyle\therefore\:\underline{\sf Time \ taken \ will \ be \ 196 sec}$

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