Question

The area A of the four walls of a room of the length L breadth b and height h is given by the formula

A=2(l+b)h find the when is a = 54m² b=4m and h = 3m

Answer 1

a=54$m^{2}$=2(l+b)h=lateral surface area of the room
b=4m
h=3m
54=2(l+4)3
3l+12=27
3l=15
l=15/3=5m
therefore length of the room is 5m

Answer 2

L = 5m , because
2h(l+b)
2*3*(l+4)=54    (because area is 54sq.m)
6(4+l)=54
4+l=54/6
4+l=9
l=9-4
l=5