The area af trapezium is 248 sq. m and its heigh 8m. if one of the parallelside is smaller the other by4m,find two parallel sides
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Question:-
The area af trapezium is 248 sq. m and its heigh 8m. if one of the parallelside is smaller the other by4m,find two parallel sides.
Answer :-
Given:
Area of trapezium= 248 m²
Height (h)= 8 m
Let the one parallel side be= x m
Other parallel side =( x-4) m
Area of trapezium = 1/2 ( sum of parallel sides) × height
248 = 1/2 ( X+ X- 4)× 8
248 = (2x - 4) × 4
248/4 = 2x-4
62 = 2x-4
62+4= 2x
66= 2x
X= 66/2
X= 33
One parallel side (X)= 33 m
Other parallel side(x-4)= 33-4= 29 m
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Step-by-step explanation:
Let the one parallel side be x then the other smaller side will be x-4
Area of trapezium = 1/2(x+ x-4)8
8x - 16=248
8x= 264
X=33
So the bigger side is 33m and the smaller side is 29m
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