Question

the area and length of one diagonal of a rhombus are given as 200 CM square and 10 cm respectively the length of other diagonal is​

Answer 1

Answer:

40 cm

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Answer 2

$\sf \bf \huge {\boxed {\mathbb {QUETION}}}$

$\begin{gathered}\tt The \:area\: and\: length\: of \:one\: diagonal\: of \:a \:rhombus\\\tt are\: given \:as \:200\: cm\: square\: and\: 10 \:cm\:respectively\\\tt the \:length \:of\: other\: diagonal \:is\end{gathered}$

$\sf \bf \huge {\boxed {\mathbb {ANSWER}}}$

$\sf \bf {\boxed {\mathbb {GIVEN}}}$

$\bf {Area\:of\:Rhombus(A) = 200 \:cm}}$

$\sf \bf Length \:of \:first \:diagonal (d_1) = 10\:cm}}$

$\sf \bf {\boxed {\mathbb {TO\:FIND}}}$

$\sf \bf Length \:of \:second\:diagonal (d_1)}}$

$\sf \bf {\boxed {\mathbb {SOLUTION}}}$

$\underline{\sf{Let\:the\:second\:diagonal\:be\:=\:x}}$

${\boxed {\boxed {\color{blue} {\sf \bf A=\dfrac{d_1 \times d_2}{2}}}}}$

$\sf{A\:=\:area \:of \:Rhombus}}$

$\sf{ d_1=first \:diagonald}}$

$\sf {d_2=second\:diagonald}}$

${\underbrace {\overbrace {\color{orange} {\sf Substituting\: the\: values}}}}$

$\sf \bf \implies 200=\dfrac{10\times x}{2}}}[tex]</p><p> </p><p>[tex]\sf \bf \implies 200\times 2=10x}}$

$\sf \bf \implies 400=10x}}$

$\sf \bf \implies x=\dfrac{400}{10}}}$

${\boxed{\sf{x\:=\:40\:cm}}$

${\color {purple} \underline {\tt \therefore The\:length \:of \:second\:diagonal \:is \:40\:cm}}$