Question

the area and perimeter of a rectangle are A and P respectively and its length is twice the breadth if the length is doubled and the breadth is tripled the area becomes A'and the perimeter P' find A':A and P':P.

Answer 1

Answer:

A':A =9

P':P =3

Step-by-step explanation:

A=X*Y

P=(X+Y)*2

A'=3X*3Y =9*X*Y

P'=(3X+3Y)*2=3(X+Y)*2=(X+Y)

SO

A':A = $\frac{9*X*Y}{X*Y}$ =9

P':P =$\frac{(X+Y)*6}{(X+Y)*2}$ =$\frac{6}{2}$ =3