Question

The area and the perimeter of a square are A and P respectively. If the sides are doubled, the
area becomes A' and the perimeter, P'. Find (i) A': A, and (ii) P':P.​

Answer 1

Step-by-step explanation:

area of square is s^2 (A)

perimeter is 4s(P)

sides are doubled

s become 2s

area (A')= (2s)^2= 4s^2

perimeter (P')= 4(2s)= 8s

1) A':A = 4s2÷s2= 4

2) P':P =8s÷4s =2

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Answer 2

Answer:

A' : A = 4 : 1  and P' : P = 2 :1

Step-by-step explanation:

If A = side²

Then A' =  (2 x side)² = 4 side²

Therefore, A' : A = 4 : 1

If P = 4 x side

Then P' = 4 x (2 x side) = 8 x side

Therefore, P' : P = 8 : 4 = 2 :1

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