The area bounded by the curve y=sin x between x=0 and x=2π is *
2 sq. units
4 sq. units
8 sq. units
None of these
Answers
Answered by
25
Answer:
4 sq. units
Step-by-step explanation
so, the required area =area OAB +area BCD = 2+2=4 sq units. i hope this will help you
Attachments:
Answered by
0
Answer:
The graph of y=sinx can be drawn as shown in the diagram.
∴ Required area =Area OABO+Area BCDB =∫ 0
π
sin x dx+
∣
∣
∣
∣
∣
∫
π
2π
sin x dx
∣
∣
∣
∣
∣
=[−cosx]
0
π
+
∣
∣
∣
[−cosx]
π
2π
∣
∣
∣
=[−cosπ+cos 0]+∣−cos 2π+cos π∣
=1+1+∣(−1−1)∣
=2+∣−2∣
=2+2=4 sq. units
Similar questions