Math, asked by Manpreet144, 6 months ago

The area bounded by the curve y=sin x between x=0 and x=2π is *

2 sq. units

4 sq. units

8 sq. units

None of these​

Answers

Answered by debajyoti39
25

Answer:

4 sq. units

Step-by-step explanation

so, the required area =area OAB +area BCD = 2+2=4 sq units. i hope this will help you

Attachments:
Answered by lalitnit
0

Answer:

The graph of y=sinx can be drawn as shown in the diagram.

∴ Required area =Area OABO+Area BCDB =∫ 0

π

sin x dx+

π

sin x dx

=[−cosx]

0

π

+

[−cosx]

π

=[−cosπ+cos 0]+∣−cos 2π+cos π∣

=1+1+∣(−1−1)∣

=2+∣−2∣

=2+2=4 sq. units

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