Question

the area bounded by the line x+y=2 and with coordinate axes is




please solve fastely urgent​

Answer 1

Answer:

Area bounded by the line x+y=10 and both the coordinate axes is 50units

2

Step-by-step explanation:

Given the line of equation x+y=10

we have to find the area bounded by the line x+y=10 and both the coordinate axes.

From the attachment,

Base=BC=10 units

Height=AB=10 units

\text{Area of triangle ABC= }\frac{1}{2}\times base\times heightArea of triangle ABC=

2

1

×base×height

=\frac{1}{2}\times 10\times 10=

2

1

×10×10

=5\times 10=5×10

=50units^2=50units

2

\text{Area bounded by the line }x+y=10 \text{ and both the coordinate axes is }50units^2Area bounded by the line x+y=10 and both the coordinate axes is 50units

2

Answer 2

The required area is 2units.

Given :

The line x+y=2 and the co-ordinate axes.

To Find :

The area bounded by the line x+y=2 and the co-ordinate axes.

Solution :

We can find the solution to this problem in the following way.

We know that the point of intersection of the line x+y=2 and the x-axis is given by putting y=0 in the line equation.

Thus, we find that the intercept of the line x+y=2 with the x-axis is 2units as denoted by the point of intersection (2,0).

We know that the point of intersection of the line x+y=2 and the y-axis is given by putting x=0 in the line equation.

Thus, we find that the intercept of the line x+y=2 with the y-axis is 2units as denoted by the point of intersection (0,2).

Therefore, the area bounded by the line x+y=2 and the co-ordinate axes is actually the area of the right-angled triangle having the base of 2 units and the height of 2 units.

We can write the following.

$Area=\frac{1}{2} \times Base \times Height\\Area =\frac{1}{2} \times 2 \times 2\\Area=2 units$

The required area that is bounded by the line x+y=2 and the co-ordinate axes, is 2units.

#SPJ3