Question

The area bounded by the lines 3x+2y=14 and 2x-3y=5 in the first quadrant ?

Answer 1

Heyaaa mate

The answer is:-

Let $3x + 2y = 14$ be i equation and $2x - 3y = 5$ be ii equation.

After multiplying i equation with 2 the answer will be

$6x + 4y = 28$

After multiplying ii equation with 3 the answer will be

$6x - 9y = 15$

$+ 6x + 4y = 28$
$-6x + 9y =-15$
______________
$0 + 13y = 13$

$y = \frac{13}{13}= 1$

To find x

Put the value of y in equation 1

$3x +2y =14$

$3x + 2(1) = 14$

$3x = 14-2$

$x = \frac{12}{2}$

$x = 6$