the area contained between the x axis and one arc of the curve y=cos3x is
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First graph the y = cos 3x.
As all cosine curves it intersects the y-axis at (0,1) but it will intersect the x-axis at (π/6, 0)
If you need the area from x = 0 to x= π/2
The integral from 0 to π/2 will give you the mpositive area, but from π/6 to π/2 will be under the x-axis so:
Area =
π/6
∫cos 3x dx -
0
π/2
∫cos 3x dx
π/6
I will leave it to you to finish the problem.
As all cosine curves it intersects the y-axis at (0,1) but it will intersect the x-axis at (π/6, 0)
If you need the area from x = 0 to x= π/2
The integral from 0 to π/2 will give you the mpositive area, but from π/6 to π/2 will be under the x-axis so:
Area =
π/6
∫cos 3x dx -
0
π/2
∫cos 3x dx
π/6
I will leave it to you to finish the problem.
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