Question

The area covered in 7 revolutions by a road roller,if its radius and height are 2 m and 4 m respectively is *


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Answer 1

Given:-

• Height of the roller = 4 m
• Radius of the roller = 2 m

To find:-

Area covered by the road roller.

Solution:-

Firstly let us clear the concept what we have to find in this question.

We know, it's the curved surface which rolls on the ground. So here too we need to find the curved surface area of the road roller.

We know,

Curved Surface Area of cylinder = 2πrh sq.units

= $\sf{CSA\:of\:roller = 2\times \dfrac{22}{7}\times 2\times 4}$

= $\sf{CSA = \dfrac{352}{7}}$

Therefore, Curved Surface Area of the road roller is $\sf{\dfrac{352}{7}}$ m²

As the roller took 7 revolutions:-

Area covered by the roller = $\sf{\dfrac{352}{7}\times 7 = 352\:m^2}$

Therefore the area covered by the toller is 352 m².

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Formula Used!!!

• $\sf{CSA\:of\:road\:roller = 2\pi rh\:sq.units}$

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Other formulas to be kept in mind!!

• $\sf{TSA\:of\:cylinder = 2\pi r(r+h)\:sq.units}$
• $\sf{Volume\:of\:cylinder = \pi r^2 h\:cu.units}$

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Answer 2

Answer:

Step-by-step explanation:

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