Question

The area enclosed by [|x|] + [|y|] = 3 is A and the area enclosed by [|x|] [|y|] = 3 is B
then

Answer 1

Step-by-step explanation:

[∣x∣]+[∣y∣].3, (given)

[x]+[y]=3,x≥0,y≥0

let 0≤x<1

x=0, then 3≤y≤4.

let 1≤x≤2

,then

2≤y≤3

let 2≤x≤3

x=2, then 1≤y≤2

let 3≤x≤4

x=3, then 0≤y≤1

Total area = 4 squnits. then =4×4

=16 squnits.