Question

the area if a square field is 1024 m square find the area of a rectangular field, whose perimeter is equal to the perimeter of the square field whose length is thrice the bredth​

Answer 1

Answer:

Given:

$Area \: \: of \: \: square=1024 {m}^{2}$

Formula used:

$Area \: \: of \: \: square= {a}^{2}$

Perimeter of square=4a

Perimeter of rectangle=2(l+b)

Area of rectangular field=l×b

Solution:

$Area \: \: of \: \: square=1024 {m}^{2}$

${a}^{2} = 1024 {m}^{2}$

$a = \sqrt{1024}$

$a = 32m$

Assumption:

Let the breath be x; and

length of rectangular field be 3x

Side of square=32m

Since,

Perimeter of square=Perimeter of rectangular

4a=2(l+b)

4(32m)=2(3x+x)

128m=2(4x)

128m=8x

x=128m/8

x=16m

Hence,

Breath of rectangular field=x

=16m

Length of rectangular field=3x

=3(16m)

=48m

Hence,

Area of rectangle=l×b

=48m×16m

$= 768 {m}^{2}$