Question

the Area
If the of Rectangle 200 m2 and length is 20m
what is the perimeter of Rectangle​

Answer 1

Answer:

60m

Step-by-step explanation:

area of a rectangle= 200

l=20m

b=?

l x b = 200

20xb = 200

b=200/20=10

Perimeter = 2(l+b)

= 2(20+10)

=2(30)

60

Answer 2

$\sf \bf \huge {\boxed {\mathbb {QUESTION}}}$

$\tt The\: Area\: If \:the \:of\: Rectangle\: 200\: {m}^{2} and\: length \:is\\\tt 20\:m\: what \:is \:the\: perimeter\: of \:Rectangle.$

$\sf \bf \huge {\boxed {\mathbb {ANSWER}}}$

$\sf \bf {\boxed {\mathbb {GIVEN}}}$

• $\sf \bf Area\:of \:rectangle = 200\:{m}^{2}$
• $\sf \bf Length\:of \:rectangle = 20\:m$

$\sf \bf {\boxed {\mathbb {TO\:FIND}}}$

• $\sf \bf Breadth \:of \:the \:rectangle$
• $\sf \bf Perimeter \:of \:the \:rectangle$

$\sf \bf {\boxed {\mathbb {SOLUTION}}}$

${\color {springgreen} \underline {\sf (i) Breadth \:of \:the \:rectangle}}$

${\boxed {\boxed {\boxed {\color {blue} {\sf \bf A=l \times b}}}}}$

• $\sf A=area\:of \:the \:rectangle$
• $\sf l=length \:of \:the \:rectangle$
• $\sf b=breadth \:of \:the \:rectangle$

${\underbrace {\overbrace {\color {orange} {\bf Substitute \:the \:values}}}}$

$\sf \bf \implies 200=20\times b$

$\sf \bf \implies b=\dfrac{200}{20}$

$\sf \bf \implies b=\dfrac{\cancel{200}}{\cancel {20}}$

${\boxed {\boxed {\color {brown} {\sf \bf b=10\:m}}}}$

${\color {magenta} {\overline {\underline {\sf\therefore Breadth \:of\:the \:rectangle \:is \:10\:m}}}}$

————————————————————————————

${\color {springgreen} \underline {\sf (ii) Perimeter\:of \:the \:rectangle}}$

${\boxed {\boxed {\boxed {\color {blue} {\sf \bf P=2\Big(l + b\Big)}}}}}$

• $\sf P= perimeter \:of \:the \:rectangle$
• $\sf l=length \:of \:the \:rectangle$
• $\sf b=breadth \:of \:the \:rectangle$

${\underbrace {\overbrace {\color {orange} {\bf Substitute \:the \:values}}}}$

$\sf \bf \implies P=2\Big(20 + 10\Big)$

$\sf \bf \implies P=2\Big(30\Big)$

$\implies{\boxed {\boxed {\color {aqua} {\sf \bf P=60\:m}}}}$

${\underbrace {\color {red} {\underline {\color {red} {\sf \therefore The\:perimeter \:of\:the \:rectangle \:is\:60\:m}}}}}$

$\sf \bf \huge {\boxed {\mathbb {HOPE \:IT \:HELPS \:YOU}}}$

__________________________________________

$\sf \bf \huge {\boxed {\mathbb {EXTRA\:INFORMATION}}}$

$\bf Perimeter \:of \:rectangle =2(l+b)$

$\bf Area \:of \:rectangle =lb$

$\bf Diagonal \:of \:rectangle =\sqrt{{b}^{2}+{l}^{2}}$

$\bf Length \:of \:rectangle =\sqrt{{d}^{2}-{b}^{2}}$

$\bf Breadth \:of \:rectangle =\sqrt{{d}^{2}-{l}^{2}}$