The area (in square units) of the region bounded by the graphs of |x|+y=4 and x+5y=−4 lies between
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K, there can be 4 cases:
|x+y| + |x-y| = 4
A. x+y+x-y = 4 --> x=2
B. x+y-x+y = 4 --> y=2
C. -x-y +x-y= 4 --> y=-2
D. -x-y-x+y=4 --> x=-2
The area bounded by 4 graphs x=2, x=-2, y=2, y=-2 will be square with the side of 4 so the area will be 4*4=16.
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