Physics, asked by vaibhavivele, 1 month ago

The area moment of inertia of shaded area about horizontal centroidal x axis in mm4
is
20 mm
40 mm 40 mm + 40 mm
k
Answer:​

Answers

Answered by syed2020ashaels
0

Answer:

The area moment of inertia of shaded area about horizontal centroidal x axis is 106.66mm

Explanation:

The moment of inertia of a rectangular section about an horizontal axis through C.G is

bd3/12.

Here breadth b=20mm

depth D=40 mm

The moment of inertia of a rectangular section about an horizontal axis through C.G is

 \frac{b {d}^{3} }{12}

 \frac{20 \times  {40}^{3} }{12}

106.66mm

The area moment of inertia of shaded area about horizontal centroidal x axis is 106.66mm

#SPJ1

Answered by pinkypearl301
0

Answer:

1,06,666.67 \mathrm{~mm}^{4}

Explanation:

A rectangle with dimensions of b and d has the following moment of inertia (MOI) about each of its centroidal axes:

\mathbf{I}_{\mathbf{x x}}=\frac{\mathbf{b d}^{3}}{12} and \mathbf{I}_{\mathbf{y y}}=\frac{\mathbf{d b}^{3}}{12}, where\mathrm{b}=width and $\mathrm{d}=$ depth of the section

Given data,

b=20 \mathrm{~mm}, \mathrm{~d}=40 \mathrm{~mm}

Now, we are aware that MOI around the $\mathrm{X}$-axis, which is a centroidal axis parallel to the breadth, is provided by

\mathbf{I}_{\mathrm{xx}}=\frac{\mathrm{bd}^{3}}{12}=\frac{20 \times 40^{3}}{12}

\therefore \mathrm{I}_{\mathrm{xx}}=1,06,666.67 \mathrm{~mm}^{4}

#SPJ1

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