the area of a circle inscribed in a in a equilateral triangle is 154 cm square find the perimeter of the triangle take root 3 equals to 1.7 to 3
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Area of the circle = 154 sq cm
therefore, πr²=154 cm²
or,22r²/7=154 cm²
or,r²=154 cm²*7/22=49 cm²
or,r=7 cm.
Let the side of the triangle be x cm.
Therefore, semi perimeter=3x/2
Radius of the circle=Area/Semi Perimeter of Δ.
or,7=(√3/4*x²)/(3x/2)
or,7=(√3*x)(3*2)
or,7=(√3*x)/6
or,7*6=√3*x
or,42=√3*x
or,42/√3=x
or,x=42/√3
Perimeter=42/√3*3=42√3=42*1.73=72.66 cm.
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