The area of a circle inscribed in an equilateral triangle is 154 cm2. Find the perimeter of the triangle.
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Area of circle = 154 cm^2
πr^2 = 154
22/7 × r^2 = 154
r^2 = 154 × 7/22
r^2 = 49
r = 7 cm
In ∆ORB, angle ORB = 90
Tan 30 = OR/RB
1/√3 = 7/RB
RB = 12.12cm
BC =2(RB)
BC = 24.24
perimeter of∆ABC = BC + AC + AB
= 24.24 + 24.24 + 24.24
= 72.74 cm
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☺ HOPE IT HELPS YOU ☺
THANKS..
_________________________________
Area of circle = 154 cm^2
πr^2 = 154
22/7 × r^2 = 154
r^2 = 154 × 7/22
r^2 = 49
r = 7 cm
In ∆ORB, angle ORB = 90
Tan 30 = OR/RB
1/√3 = 7/RB
RB = 12.12cm
BC =2(RB)
BC = 24.24
perimeter of∆ABC = BC + AC + AB
= 24.24 + 24.24 + 24.24
= 72.74 cm
_________________________________
☺ HOPE IT HELPS YOU ☺
THANKS..
Answered by
1
72.74 is the answer of the question
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