the area of a circle interrupted in a equilateral triangle is 154 cm square find the perimeter of the triangle
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We know that,
πr²=area of a circle then the equation is
then,
πr²=154
=>22/7×r²=154
=>22×r²=22
=>r²=1
=>r=1
We know that,
2πr=diameters of a circle
then,
2πr
=2×22/7×1
=44/7
=6.285 approx.
hope it helps
if it correct give a like and mark as brainlist either comment
πr²=area of a circle then the equation is
then,
πr²=154
=>22/7×r²=154
=>22×r²=22
=>r²=1
=>r=1
We know that,
2πr=diameters of a circle
then,
2πr
=2×22/7×1
=44/7
=6.285 approx.
hope it helps
if it correct give a like and mark as brainlist either comment
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